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Dishonored®: Death of the Outsider™ – Jindosh’s Locks (Mission 3) – The Code

15 September 2017, Friday, 14:39:33


Jindosh’s Locks (Mission 3) – The Code

How to Crack the Code

Left to right, the code is 011, 235, 813, 455, 891

Basically the blank 2 key safe stuffs up the code. You need to imagine it still has 3 turning tiles on it for this to work.
The code is not random but the way you work out the next number is by taking the previous 2 numbers and adding together. The code you are given at the start goes 0,1,1,2,3,5,8,13…..

-To work out the next number you add 13 and 8 together leaving 21.
-The next safe is the 2 key safe. Simply imagine it has inputs on it like all the others.
-So then do 21 + 13 yielding 34.


-The 3 would go on the end of the 2 key safe and the four as the first number on safe number 5.
-Then 34 + 21 = 55 so input 55 on the next 2 uncoded inputs. Keep the sequence going.


Dishonored®: Death of the Outsider™ – All Combinations For Each Individual Safe

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Name : Morgan | Comment Date : September 15th, 2017

This is good! Now I need the lockbox codes for Morgan Yu and Cristofer Jeorge in the basement of the bank! I can’t find any papers with any hints on ;(

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